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9n^2-4=464
We move all terms to the left:
9n^2-4-(464)=0
We add all the numbers together, and all the variables
9n^2-468=0
a = 9; b = 0; c = -468;
Δ = b2-4ac
Δ = 02-4·9·(-468)
Δ = 16848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16848}=\sqrt{1296*13}=\sqrt{1296}*\sqrt{13}=36\sqrt{13}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{13}}{2*9}=\frac{0-36\sqrt{13}}{18} =-\frac{36\sqrt{13}}{18} =-2\sqrt{13} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{13}}{2*9}=\frac{0+36\sqrt{13}}{18} =\frac{36\sqrt{13}}{18} =2\sqrt{13} $
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